The cylinder diameter is 20 cm,then radius r 10 cm R, let the radius of the ball=5 cm Volume of a sphere V=(4/3)NR^3.Then:\r\n\r\nπ(r^2)*h=(4/3)π*R^3, where h is the difference of old and new heights of water cylindre;\r\n\r\palee: h=((4/3)*5*5*5)/(10*10)=1,67 see it did not seem wrong.

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Malolar

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