Perimeter of a rectangle of 48 dm its width is 1/2 part of its length Find lengths of the parties of this rectangle

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X length 1/2kh width (x +1/2kh) *2=48 x +1/2kh =48:2 x +0.5kh =24 1.5kh =24 x =16 dm length of 16*1/2=8 cm width Let x length, then width 1/2kh or 0.5kh (x +0.5kh) *2=48 1.5kh =24 x =16 dm is long a rectangle of 16*0.5=8 dm rectangle width. Answer: 16 dm. and 8 dm. Check: 8+16+8+16=48 48=48 (truly).
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