# To the pool three pipes are brought. The first pipe fills the pool with water for 6 h, and the second - for 8 h. On the third pipe water from the filled pool flows for 4 h completely. What part of volume of the pool is filled with water for an hour if water flows at the same time on three pipes? 306
We THINK Tasks about pipes it is possible to compare to tasks about a way. Formulas are approximately identical. And = p*t is work. Formulas r = A: t - pipe performance - t speed = A: p - time the Pool at us ONE - And = 1 - should be filled ONE pool. t1 = 6 t2 = 8 t3 = 4 Pc = is GIVEN to p1+p2 - p3 - the joint performance of pipes - two pour, the third - merges. To FIND t4(1) = - a part of the pool for 1 hour of work of three pipes. SOLUTION 1) of p1 = A/t1 = 1/6 (1/h) - the performance of the first pipe. Similarly 2) r2 = 1/8 and r3 = 1/4. We write the main equation of a task. at t = 1 hour 3) And * (1/6 + 1/8 - 1/4) = = A*(4+3-6)/24 = A*1/24 the ANSWER In 1 hour will be filled (HOK=24) 1/24 part of the pool. IN ADDITION Time of filling of the pool completely. T = A: 1/24 = 24 h - will be filled the pool.
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