For breakfast Carlson ate 40 percent of cake, and Malysh ate 150 g. For lunch Fröken Bock ate 30 percent of the rest and 120 more g, and Matilda licked the remained 90 g of crumbs from cake. What weight there was a cake initially? (are grams)

145
1) 90 + 120 = 210 (g) of cake remained after As Fröken Bock ate Fröken Bock of the village of the 30th rest the 30th rest, 210 g are the 70th rest. 2) 210: 0.7 = 300 (g) of cake were before Fröken Bock started a lunch. 3) 300 + 150 = 450 (g) of cake were before Malysh began to eat. As Carlson ate the 40th cake, 450 g make the 60th cake. 4) 450: 0.6 = 750 (g) initial mass of cake.----------------------------------------------------------------------------------------------------The second way (we work out the equation). Let x — the initial mass of cake, then after tomorrow Carlson and Malysh remained 0.6x−150 (), after Fröken lunch Bock remained 0.7 (0.6x−150) −120 == 0.42x−225 () that makes 90 g licked by Matilda. Let's receive the equation 0.42x−225 = 90 which decision is x = 750.

For breakfast Karloson ate the 40th cake, and Malysh ate 150 grams. For lunch Fröken Bock ate the 30th rest and 120 more g, and Matilda licked the remained 90 g of crumbs from cake. What weight there was a cake initially

Answer's

:

Hg-100-ves Karloson-0.4X Malysh cake - 120 g Fröken the Side-0.3 (0.4X) Matilda - 90 g 0.4X +120+0.3(0.4X)+90=X 360=0.48 X=750 of Answer: 750 g

188
Answer add