In three aquariums 82 small fishes. How many small fishes in each aquarium if in the second is 5 small fishes more, than in the first, and in the third are 6 small fishes more, than in the second? 15 POINTS

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82-6=76 (small fishes) We removed excess small fishes from the 3rd aquarium. 76-5-5=66 (small fishes) We removed excess small fishes from the 2nd and 3rd aquarium. 66:3=22 (small fishes) in the first aquarium. 22+5=27 (small fishes) in the second aquarium 27+6=33 (small fishes) in the third aquarium we Will work out the equation. x - quantity of small fishes in the second aquarium. Then in the first x-5, and in the third x+6 of small fishes of x+x-5+x+6=82 2x-5+x=82-6 2x-5+x=76 3x=76+5 3x=81 of x=81:3 x=27 27+27-5+27+6=82 82=82 2)27-5=22 (small fishes) - the first aquarium of 3)27+6=33 (small fishes) of Answer: in the first aquarium 22 small fishes, in the second 27, in the third 33.
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