# Two workers working in common can perform work in 6 hours, one of them working independently in 15 hours. In how many hours will other worker perform this work, working independently?

Umfyn

149

1/6 performance both 1/15 performance the first 1/6-1/15=5/30-2/30=3/30=1/10 productivity of the second 1รท1/10=10 during this time will make the second

262

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ruska

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