At noon the steamship which moved with a speed 35km/h in 2 watch from the same pier in the same direction departed from pier the second steamship which in 10 hours after an exit caught up with the first departed. determine the speed of the second steamship

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10 + 2 = 12 hours time in a way of the first steamship 35 * 12 = 420 km distance from pier to the meeting place of steamships 420/10 = 42 km/h the speed of the second parokhoda1. 35*(10+2)=420 (km) - the first passed, prior to a meeting 2. 420:10=42 (km/h) - the speed of the second
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