The sum of three numbers is equal to 234. The first is 32 less than an arithmetic average of these numbers, and the second is twice more than the sum of these two other numbers. To find these numbers.

X+y+Z=234 x+y+z/3-x=32 y=2x+2z 2x+2z+x+z=234 3x+3z=234 x+z=78 y=2X78=156 156+78/3-x=32 78-x=32 of x=46 46+z=78 z=32
Answer add