Length of a rectangle is 3 times more party of a square, and width - is 5 cm less than the party of a square. Find the party of a square if its area is 50 cm² less than the area of a rectangle. Help to solve please. And if it is possible, then the full decision, t.e "Let x.... " well or that that similar. In advance, bolshooooy thank you. Very urgently it is necessary.

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The party of quarter - the X Dl. it is direct. - 3X Scheer. it is direct. - (H-5) of Skv = X² Spr =3X×(X-5) x²+50=3x(x-5) x²-3x²+15x²+50=0 - 2x²+15x+50=0 D=225+400=625 x ₁= (-15+25)/-4=-10/4 x ₂= (-15-25)/-4=10 Party of a square of =10 cm.
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