The settlement at the same time in the prltivlozhny directions left two pedestrians. In 3 h the distance between them was equal to 27 km. One of them went with a speed 4km/h. With what skoromtyu there was the second pedestrian

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1) 4*3=12 km - there passed the first pedestrian 2) 27-12=15 km - there passed the second pedestrian 3) 15:3=5 km/h or 1) 27:3=9 km/h - the speed of a distance 2) 9-4=5 km/h the answer: 5 km / ч1) 4*3=12 (km) - there passed 1 pedestrian 2) 27-12=15 (km) - there passed the 2nd pedestrian 3) 15:3=5 (km/h) - there was the 2nd pedestrian Answer: 5 km/h speed is 2 pedestrians
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