3. In the internal area of a right angle of AVS such point of M is noted that BAM =200 corner, BCM=100 corner. Find AMS corner.

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∠AMC = 360 ° – ∠ABC – ∠BAM – ∠BCM = 360 ° – 90 ° – 200 ° – 100 ° = –30 ° — a quadrangle with the sum of corners more than 360 ° does not exist. Answer's : there are no decisions.
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Answer add