Two cyclists left on a meeting each other in 10 h morning and met in 13 h. What is the time there was in way each cyclist? What distance was between them originally if one cyclist speeded at 16 km/h, and other-18 km/h. Help to solve.

113

13-10=3 hours there was in way each cyclist

of 16*3=48 (km) 1 cyclist prior to a meeting

passed

of 18*3=54 (km) the 2nd cyclist prior to a meeting

passed

of 48+54=102 (km) the distance between them was originally.

198
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