Straight lines of MN CD EF are crossed in a point of O AOE=55 DOF=25. find a-degree measure of corners of BOE and BOD

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1) DOF= corner to corner SOE=25gradusov (as vertical); AOE Corner = COE+ COA = 55=gt; COA=55-25=30, SOA corner = BOD=30 degrees (as vertical) corner of EF of =180 degrees = COE+ corner SOA corner + corner of AOF=25+30+ AOF; AOF 180-25-30=125ugol AOF = to a corner of BOE=125 degrees (as vertical)
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