The ice breaker opened 3 days the way in ices. In 1 day it floated 2/5 all ways, in 2 day-5/8 the remained ways, and in 3 day - the remained 90 km. What is the way which floated the ice breaker for 3 days of traveling equal to? How many kilometers did it float in 1 and 2 day? It is possible to explain clear as in the equation and without it you can solve.

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We find what way passed the ice breaker for the second and third day: 90: 3 • 8 = 240 km. Now we will take for whole all way and we will find what share of a way needed to be passed to the ice breaker for the second and third day: we find all way which passed the ice breaker in three days: 240: 3 • 5 = 400 km. we find what way passed the ice breaker for the first and second day: 400: 5 • 2 = 160 km – in the first day; 240: 8 • 5 = 150 km – in the second day. Answer's . In the first day the ice breaker passed 160 km, in the second day – 150 km; in three days – 400 km
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