# Solve the equation of K.m/1.8+2.05=9; L.n/5=63-56.08; A.k/8-6.09=6; I.z/19.63+0.37=8.376;.x/78.09+21.91=0.736; Highway at / 98.35-83.17=7

Rodion

1

of m/1.8+2.05=9; m: 1.8 = 9 - 2.05 m: 1.8 = 6.95 m = 6.95 × 1.8 m = 12.51 of n/5=63-56.08; n: 5 = 6.92 n = 6.92 × 5 n = 34.6 k/8 - 6.09 = 6; k: 8 = 6 + 6.09 k: 8 = 12.09 k = 12.09 × 8 k = 96.72 of z/19.63+0.37=8.376; z: 19.63 = 8.376 - 0.37 z: 19.63 = 8.016 z = 8.016 × 19.63 z = 157.35408 x/78.09+21.91=0.736; x: 78.09 = 0.736 - 21.91 x: 78.09 = −21.174 x = ( −21.174) × 78.09 x = −1653.47766 at / 98.35 - 83.17=7 at: 98.35 = 7 + 83.17 at: 98.35 = 90.17 at = 90.17 × 98.35 y = 8868.2195

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Terry Gabriel

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