# From the village to the city between which distance of 78 km, the cyclist left and at the same time towards to it the city was left by the motorcyclist. Speed of the cyclist is 13 km/h, and - it is twice more motorcyclist. In how many hours will they meet? Help please with the decision!

Chernopyatov

370

13*2=26 km/h - the speed of the motorcyclist of 13+26=39 km/h - the speed of rapprochement are 78:39=2 hours - time of a meeting of Answer: through 2 chasa78 / (13*2+13) =2chasa here so

339

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rumyana

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