Condition with the decision and the return tasks one car stayed on the way 12 hours and another the first arrived the 8th hour 400 km more than the second what distance was passed by them if speed is identical

12-8=4(ch) 1 car of 400:4=100 km/h the speed of 12·100=1200 km went longer 1 car of 8·100=800 km passed the 2nd car passed I Hope helped :)
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