Calculate a sine of the angle of ABC in a rectangular triangle with a right angle of C if it is known that: a) AB=3 cm, BC=1 cm; b) AC=3 cm, BC=1 cm.

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Calculate a sine of the angle of ABC in a rectangular triangle with a right angle of C if it is known that: a) AB=3 cm, BC=1 cm; AC= √ (AB²-BC²)= √ (3²-1²) =2√2 of sin ∠ABC=AC/AB = (2√2)/3 b) of AC=3 cm, BC=1 cm AB= √ (AC²+CB²)= √ (9+1)= √ 10 sin∠ABC=AC/AB = 3 / √ 10=3√10/10
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