The basis of an isosceles triangle is equal 6, and length of height which is carried out to the basis is equal to length of the piece connecting the middle of the basis and side. Find value of expression of S * √ 3 where S is the area of a triangle.

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In ∆ ABC AB=BC.

of VN height is span>.

Height of an isosceles triangle which is carried out to the basis, both a bisector and a median.

H.

On BH=HM condition.

of NANOMETER - the AVS average line.

of of VM =0.5 AB = 0.5 BC .

of BH=BM=HM, ∆ VNM - equilateral. NVM corner = 60 °

B ∆ VNS C=30 corner °, and HC =AC/2=3

ВН=НС:tg60°

ВН=3:√3=√3

S=AC•BH:2=3•√3

3√3:√3=3 Height (area unit)

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