From two settlements between which 26 km, towards each other left two pedestrians. In 2 hours the distance between them was reduced to 6 km. With what speed there were pedestrians if it is known that one of them passed in an hour 2 km bigger than another.

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Let X - km/h - the speed of the first pedestrian, then (X +2) km/h - the speed of the second pedestrian They passed in two hours 1) 26-6=20 km 2) (X + (X +2)) * 2 = 20 (2X + 2) * 2 = 20 4X + 4 = 20, 4H = 20-4=16, H =16: 4 = 4 m/h the speed of the first pedestrian 3) 4+2 = 6 km/h - the speed of the second pedestrian Proverk: 4 * 2 + 6 * 2 = 8 + 12 = 20 First 6 km/h. and another 4km/h
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