Perimeter of a square of 64 cm. Find length of a rectangle which width is equal to 4 cm, and the area twice smaller, than the area of a square.

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1) 64:2=32 (quarter cm) - the area of a rectangle 2) 32:2=16 (cm) - 2 parties of a rectangle (1 length and 1 width) 3) 16-4=12 (cm). Answer: 12 cm length of a rectangle

1) 64: 4 = 16 (cm) - 1 party of a square

2) 16 * 16 =256 (sq. cm) - the area of a square

3) 256: 2=128 (sq. cm) - the area of a rectangle

4) 128:4=32 (cm) - rectangle length

of Answer: length of a rectangle is 32 cm

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