What of numbers – 1, 2, 3 – are an equation root: a) x + (x +3) = 7; b) (the 2nd – 1)+ (x +3)=6; c) (x – 1) (x +2)=4; d) (the 3rd +2) (x – 2)=11?

98
A) 2x+3=7 2x=7-3 2x=4 x=2 answer: 2 A) x+(x+3)=7 x+x+3=7 2x=4 of x=2 í)(2x-1)+ (x+3) =6 2x-1+x+3=6 3x=4 x=4/3 B) (x-1) (x+2) of =4 x^2+2x-x-2-4=0 x^2+x-6=0 X1=3 X2=-2 D) (3x+2) (x-2) =11 3x^2-6x+2x-4-11=0 3x^2-4x-15=0 D=16+180=196 X1.2= (4+-14)/6 X1=18/6=3 X2 =
242
Answer add