From Paragraph A the car with a speed of 60 kilometers of hour in 4 hours moved to Paragraph B of 555 km From Paragraph A in Paragraph B was left by the bus which speeded at 75 percent from 60 km/h through how many they will meet

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60*4=240 (km) were passed by the car before departure of the bus of 555-240=315 (km) between the car and bus at the time of departure of the bus of 60 km/h: 100*75=45 km/h the speed of the bus is 60+45=105 (km/h) the speed of rapprochement is 315:105=3 (h) 3+4=7 (h) Answer: they will meet in 7 hours after departure of the car and in 3 hours after departure of the bus
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Answer add