# Given a triangle of ABC; AM and CE - a median to Find Perimeter of a triangle of ABC if AC = 18 cm; AE = 10 cm; CM = 8 cm.

Thoril

2

AM and SE of a median. They divide the parties into two equal pieces. Cm AE=EB=10 turns out; CM =MB =8 see Perimeter - the sum of lengths of all parties. It turns out: 20 cm +16sm +18sm =54sm. Answer: 54 cm.

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Anton

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