Two skiers move towards each other on ring. The first with a speed of-8.3 km/h, the second is 1.9 km/h faster. Every 0.4 hour they meet. What length of the route

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From a meeting and prior to a meeting (t = 0.4 h) skiers totally pass a cycle. S1 = V1 * t = 8.3 * 0.4 = 3.32 (km) of V2 = V1 + 1.9 = 8.3 + 1.9 = 10.2 (km/h) of S2 = V2 * t = 10.2 * 0.4 = 4.08 (km) of S = S1 + S2 = 3.32 + 4.08 = of 7.4 (km)
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