Direct AV, CD and EF are crossed in a point O. Prichm by AV CD & lt; = 30 Degrees Find AOE a-degree measure of a corner of COF

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AB ⊥ CD. O - point of intersection of direct AB, CD, EF. ∠AOE = 30 °. = AB we will arrange ∠COF horizontally, this straight line will be the developed corner and will be equal 180 °. Knowing that AB ⊥ CD, corners will be straight lines, i.e. on 90 ° everyone (these are corners of AOD, BOD, AOC, BOC). But the straight lines located on the developed corner gain property of adjacent corners. From here, ∠COF = AB - ∠AOE - ∠BOC = 180 ° - 30 ° - 90 ° = 60 °. Answer: ∠COF = 60 °.
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Answer add