# HELP to SOLVE the DIFFICULT PROBLEM! At collaboration the master and his pupil for 2 hour of work can obrabotat24 details For what time at preservation of the same performance one pupil if productivity of the master on 6 it is put / h higher, than performance UCHENIKARESHAYETSYA OUT OF HOW MANY ACTIONS WITHOUT X THANKS IN ADVANCE will be able to process these 24 details

Sadok

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24:2 = 12 details in 1 hour are done by the master and the pupil. 12-6 = 6 it is put / h - the doubled productivity of the pupil. 6:2 = 3 it is put / h - productivity of the pupil. 24:3 = 8 h will be required to the pupil.1) 24÷2 = 12 2)12-6 = 6 3)6÷2 = 3 4)24÷÷3 = 8

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Shelton Cameron

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