How many rectangles with the parties of 1 dm and 1 cm can be laid in a rectangle with the parties 1 dm and 7 cm?

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Given: and ₁ = 1 dm = 10 cm; b ₁ = 1 cm; a ₂ = 1 dm = 10 cm; b ₂ = 7 cm of S /S ₁ — Resheniye: S ₁ = a₁b ₁ = 10*1 = 10 (cm²), S ₂ = a₂b ₂ = 10*7 = 70 (cm²). S /S ₁ = 70/10 = 7. Answer: 7. I believe that so, 10:10=1; 7:1=7; 7*1=7 rectangles
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