From a camp site to the city at ten o'clock of morning there was a skier and at 15 o'clock in the same direction the rider through what time the rider left will catch up with the skier if the skier izht with a speed of 10 km in the h and the rider speeds at 25 km in the h

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15-10=5 Time which the skier before departure of the rider passed 5*10=50 Distance which the skier before departure of the rider passed 25-10=15 Speed with which the rider catches up with the skier 50/15=3.3 Distance which was passed by the skier before departure of the rider we divide into Speed with which the rider catches up with the skier Na and unless a formula of time t=s/u of Answer in 3 hours and 3 minutes
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Answer add