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Let the first part of a way to a delay at a semaphore the locomotive followed according to the schedule. I.e. all delay just is also 10 min. =1/6 hours. To a delay the locomotive passed 200*0.45=90 km Means it was necessary to pass to it 200-90=110 km Let the initial speed of a locomotive was x km/h. Then, following with this speed it would pass 110 km during hours. Making up for the schedule, it moved with a speed (x+5) of km/h. Also overcame these 110 km during hours. According to a condition I.e. we receive the equation Here its darling and we will solve. ₂ we reject root x. And here x ₁ quite suits us. ANSWER: Initial speed of a locomotive is equal to 55 km/h
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