Two regular intercity buses at the same time left one city in another. Speed of one of buses is more than another on 20 km/h therefore it came on an hour earlier. Knowing that distance between the cities of 120 kilometers, find the speed of the fastest bus.

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X - the speed of low-speed bus 120/x - 120 / (x +20)=1,120 * (x +20) - the 120th = x (x +20) the 120th +2400-120kh = x²+20х x²+20х-2400=0 x =-10± √ 100+2400=-10+50=40 km/h the Speed of the fastest bus 40+20 = 60 km/h
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