Calculate the area of a rectangle if one its party is twice more, and the perimeter is equal to 120 cm... Help please

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R a rectangle = 2 (a + b) S rectangles = ab 1) ★ Let x cm - length of one party of a rectangle, and (2) cm - length of its second party, then: 2 (x + the 2nd) = 120 2 × 3x = 120 6x = 120 x = 120/6 x = 20 (cm) - length of one party of a rectangle. ★ 2 × 20 = 40 (cm) - length of the second party of a rectangle. 2) Rectangle S = 20 × 40 = 800 (cm²) of Answer: 800 cm²
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