# Solve a problem. In two runduka aft yachts "Hope " lie 6 maps. For cards from one runduk 120 rubles, and are paid for cards from other runduk of 240 rubles. Question: How many maps lie in each runduk if all of them have the identical price? I GIVE 12 POINTS

Vissarion

10

240-120=(120+240):6=60 cost of 1 card 120:60=2 in 1 chest 240:60=4 in the 2nd chest of Proverk: 2+4=6pust x - the card price. then we have the equation 120/x + 240/x = 6,360/x = 6 x = 360/6 x = 60 V the first runduk 120:60 = 2 cards In the second 240:60 = 4 cards

112

Answer add
genoveva

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