Two bicycles left at a meeting each other in 10 h morning and met in 13 h. What is the time there was in way each cyclist? What distance was between them originally if one cyclist speeded 16 kmch, and another - 18 kmch?

184
13-10=3ch 16+18=34 34*3=102km

was 3-10=3 hours in way each cyclist

of 16*3=48 (km) 1 cyclist prior to a meeting

passed

of 18*3=54 (km) the 2nd cyclist prior to a meeting

passed

of 48+54=102 (km) the distance between them was originally.

57
Answer add